2022成都一诊考试答案

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1、若收敛，则也收敛.
答案：正确
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2、Manganese dioxide will accelerate hydrogen peroxide decompose.
A:正确; B:错误
答案：正确
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3、营销渠道的宽度是指（ ）

营销渠道的宽度是指( )。
A．中间商总数 B．批发商总数
C．零售商总数 D．同一层次中间商数
答案：D
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4、将某些商品定低价来吸引顾客购买更多商品，这种策略叫做（ ）：
A、声望定价
B、尾数定价
C、招徕定价
D、季节折扣
答案：声望定价
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5、Which is not correct statement about bromine?
A:Bromine is a dark brown liquid at room temperature, which is very volatile
B:Bromine is highly corrosive to metals, and it can cause an explosion in case of ammonia, hydrogen and other gases
C:When storing bromine in the laboratory, place it in a colorless reagent bottle, add water to form a water seal
D:Bromine shall not be stored in the same warehouse with organic substances, reducing agents and oxidants
答案：When storing bromine in the laboratory, place it in a colorless reagent bottle, add water to form a water seal
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6、幂级数的收敛域为（）
A、(-e, e)
B、
C、
D、[-e, e)
答案：第一空：
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7、函数项级数在实数域上一致收敛
答案：错误
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8、下列级数发散的是（ ）
A、
B、
C、
D、
答案：C
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9、Which method should be used to evacuate in the initial stage of fire
A. From Windows Firewall with Advanced Security, view the quick mode security association.
B. From Event Viewer, search the Application Log for events that have an ID of 1704.
C. From Event Viewer, search the Security Log for events that have an ID of 4672.
D. From Windows Firewall with Advanced Security, view the main mode security association.
答案：D
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10、求级数的和。
答案：解收敛半径R=lim(n1)/n=1,收敛区间为(-1,1),收敛域也是(-1,1),在收敛域内设和函数为s(x),则s(x)==xs1(x),s(0)=0,对s1(x)=在[0,x]上求定积分得，两边求导得到s1(x)=1/(x-1)2,所以s(x)=x/(1-x)2.
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11、级数发散。
答案：正确
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12、关于函数列，下列叙述正确的有
A、在实数域上一致收敛;
B、在实数域上内闭一致收敛;
C、极限函数在实数域上存在导函数;
D、极限函数在实数域上可积.
答案：在实数域上内闭一致收敛;; 极限函数在实数域上存在导函数;; 极限函数在实数域上可积.
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13、对于任意收敛的正项级数，总是存在常数使得除去有限项外，满足
答案：错误
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14、可以根据函数的傅里叶级数得到
答案：正确
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15、级数条件收敛
答案：必收敛；
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